Respuesta :
oxid # : 0 0 +2 -1
[tex]equation:Cl_{2} + Ni -----\ \textgreater \ Ni^{2+} + 2Cl ^{-}[/tex]
∴ the nickel was oxidized while chlorine was reduced
nickel reduction potential = - 0.25 V
but since it is being oxidised the you have to switch the integer sign so the
the potential of nickel in this case becomes + 0.25 V
chlorine was reduced thus its reduction potential remains same = + 1.36 V
Overall Cell potential = ∑ of half cell potential
The overall cell potential = (+ 1.36) + (+ 0.25)
= + 1.61 V
∴ the answer would be D
[tex]equation:Cl_{2} + Ni -----\ \textgreater \ Ni^{2+} + 2Cl ^{-}[/tex]
∴ the nickel was oxidized while chlorine was reduced
nickel reduction potential = - 0.25 V
but since it is being oxidised the you have to switch the integer sign so the
the potential of nickel in this case becomes + 0.25 V
chlorine was reduced thus its reduction potential remains same = + 1.36 V
Overall Cell potential = ∑ of half cell potential
The overall cell potential = (+ 1.36) + (+ 0.25)
= + 1.61 V
∴ the answer would be D
The overall cell potential for this redox reaction is 1.61 V. option D is correct.
What is cell potential?
Cell potential is measured in the electrochemical series of the electrochemical cell mainly it measures the potential difference between the two electrodes.
These two electrodes are known as the cathode electrode and the anode electrode when any redox reaction happens first half of a cell is cathode reaction and second half is known as anode reaction.
The cell potential for this redox reaction,
E°cell = E°red - E°ox
E°red = - 1.36
E°ox = - 0.25
substituting the values,
E°cell = (- 1.36 V) - (-0.25 V)
E°cell = 1.61 V
Therefore, overall cell potential for this redox reaction is 1.61 V. option D is correct.
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