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A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).

Respuesta :

Ckaranja
The lines have equal gradients;
m[tex] \frac{16}{20} = \frac{4}{5} [/tex]

Equation of line 2;
y=mx+c
y=[tex] \frac{4}{5} [/tex]x+c
-15=[tex] \frac{4}{5*(-5)} [/tex]+c
c=-11
y=4/5x-11

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