Respuesta :
Standard form for quadratic equations is:
ax² + bx + c = 0
Therefore, in Mischa's equation, the value of c is -7.
ax² + bx + c = 0
Therefore, in Mischa's equation, the value of c is -7.
Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form
The standard form of quadratic equation is
[tex] y= ax^2 + bx + c [/tex]
When y=0 then the standard equation becomes
[tex] 0= ax^2 + bx + c [/tex]
Now we compare the given equation [tex] 0 = -x^2 + 4x - 7 [/tex] with [tex] 0= ax^2 + bx + c [/tex] and find the value of a, b,c
-x^2 can be written as -1x^2
[tex] 0= ax^2 + bx + c [/tex]
[tex] 0 = -1x^2 + 4x - 7 [/tex]
a= -1 , b=4 and c=-7
The value of c is -7
