contestada

A box contains 48 tickets for six door prizes. Six tickets are drawn, and not replaced, to declare the winners. If serge purchases 8 tickets, determine the probability that he wins
a) the first prize
b) the first and second prizes
c) all six prizes

Respuesta :

the tickets aren't replaced, so multiply the probabilities, decreasing the  denominator each time.

a) 1/48
b) (1/48)(1/47)
c) (1/48)(1/47)(1/46)(1/45)(1/44)(1/43)
toporc
a)[tex]P(1st\ prize)=\frac{8}{48}[/tex]
b)[tex]P(1st+2nd\ prizes)=\frac{8C2}{48C2}=.025[/tex]
c)[tex]P(all\ 6\ prizes)=\frac{8C6}{48C6}=0.000002[/tex]