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A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant current during the discharge, what is the duration of this lightning bolt?

Respuesta :

adelekeademolu

Answer:

[tex]1.65\times {-3} \text { s}[/tex]

Explanation:

Current is the rate of flow of charge.

[tex]I=\dfrac{Q}{t}[/tex]

[tex]t = \dfrac{Q}{I} [/tex]

[tex]t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}[/tex]

JhoanEusse

Answer:

The duration of the lightning bolt is 1.65 milliseconds

Explanation:

Current is a physical quantity that tells how much charge (q) pass through a specific surface, and its unit on the International system of units is the ampere (A), that is coulomb over time [tex] \frac{C}{t}[/tex]. So current equation is:

[tex] I=\frac{dq}{dt}[/tex]

If I is constant then the equation becomes:

[tex]I= \frac{Q}{t} [/tex]

With Q the net charge

Solving for t:

[tex]t=\frac{Q}{I}=\frac{30.0C}{18.2\times10^3A} [/tex]

[tex] t=1.65\times10^{-3}s=1.65 ms[/tex]

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