How you you work out this question?

Answer:
k<0 or k>4
Step-by-step explanation:
In the generic equation ax² + bx + c = 0, there are two solutions only if discriminant D>0 where D = b²-4ac.
Mapping your equation on the generic means that:
a = k
b = k
c = 1
So when we have to solve D>0 we solve:
k² - 4k > 0
k(k-4) > 0
roots are k=0 and k=4
k² - 4k > 0 when k<0 or k>4
Answer:
k < 0 or k > 4
Step-by-step explanation:
kx² + kx + 1 = 0
Two solutions:
b²-4ac > 0
(k)²-4(k)(1) > 0
k² - 4k > 0
k(k-4) > 0
k < 0 or k > 4