In a bank of 320 staffs, 120 speak French, 140 speak English, 170 speak Arabic, 50 speak both French and English, 35 speak both English and Arabic, 40 speak both French and Arabic. Required ; (a) Determine the number of staffs who speak all the three​

Respuesta :

I have no idea what the answer is

The number of staffs that speak all three languages is 5

How to determine the common difference

If there are three sets, use the formula

n(F∪E∪A) = n(F) + n(E) + n(A) - n(F∩E) - n(E∩A) - n(F∩A) + n(F∩E∩A)

Where F = French = 120 staffs

E = English = 140 staffs

A = Arabic = 170 staffs

F∪E∪A = total number of staffs = 320 staffs

F∩E = 50 staffs

E∩A = 35 staffs

F∩A = 40 staffs

F∩E∩A = Number of staffs that speak all three languages, that is the common difference

Substitute into formula

320 = 120 - 140 - 170 - 50 -35 - 40 + F∩E∩A

320 = 315 + F∩E∩A

Make F∩E∩A subject of formula

F∩E∩A = 320 - 315

F∩E∩A = 5 staffs

Therefore, the number of staffs that speak all three languages is 5

Learn more about Venn diagram here:

https://brainly.com/question/4910584

#SPJ9