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Victoria has $1.90 worth of nickels and dimes. She has 2 more nickels than dimes.
Write a system of equations that could be used to determine the number of nickels
and the number of dimes that Victoria has. Define the variables that you use to write
the system.

Respuesta :

Answer:

0.05n+0.10d=1.90

n=d+2

Step-by-step explanation:

One nickel is worth $0.05, so n nickels are worth 0.05n. One dime is worth $0.10, so dd dimes are worth 0.10d.The total 0.05n+0.10d equals $1.90:

0.05n+0.10d=1.90

Since there are 2 more nickels than dimes, there are more nickels, so if we add 2 to the number of dimes, we will get the number of nickels, meaning nn equals d+2.d+2.

n=d+2

The system of equations is  0.05n+0.10d=1.90  and n=d+2

  • The calculation is as follows:

We know that

One nickel = $0.05,

So n nickels are worth 0.05n.

One dime = $0.10,

so dd dimes are worth 0.10d.

Now

The total 0.05n+0.10d =  $1.90

i.e.  

0.05n+0.10d=1.90

And,  

n=d+2

Therefore we can conclude that The system of equations is  0.05n+0.10d=1.90  and n=d+2

Learn more: brainly.com/question/17429689