Answer:
[tex]PQ=40\ ft[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle OPQ
[tex]cos(P)=\frac{PQ}{OP}[/tex] ----> by CAH (adjacent side divided by the hypotenuse)
substitute the given values
[tex]cos(54^o)=\frac{PQ}{68}[/tex]
solve for PQ
[tex]PQ=(68)cos(54^o)=40\ ft[/tex]