Find a 7th term of the geometric sequence whose common ratio is 3 / 2 and whose 1st term is 6. BRANLIEST ASAP TY!!!!!

Answer:
here; r=3/2
a1=6
we have to find a7=?
as we know that
an=ar^(n-1)
by substituting values
a7=6(3/2)^6
=6(729/64)
=2187/32
Answer: 68.34
Step-by-step explanation:
Formular for geometric sequence An = A1r(n - 1); An=A7, r=3/2; a1 =6, n =7
By slotting in the figures in the formula, it gives 6 (729/64)
6(11.39)
68.34