Respuesta :
Answer:
[tex]C(p)=50p+400[/tex]
Step-by-step explanation:
Let p represent number of phones produced in one day.
We have been given that Allison must pay a daily fixed cost to rent the building and equipment, and also pays a cost per phone produced for materials and labor. The daily fixed costs are $400 and and the total cost of producing 3 phones in a day would be $550.
Let x represent cost of each phone.
We can represent this information in an equation by equating total cost of 3 phones with 550 as:
[tex]3x+400=550[/tex]
Let us find cost of each phone.
[tex]3x=550-400[/tex]
[tex]3x=150[/tex]
[tex]x=\frac{150}{3}[/tex]
[tex]x=50[/tex]
Since cost of each phone is $50, so cost of p phones would be [tex]50p[/tex].
The total cost would be equal to cost of p phones plus fixed cost.
[tex]C(p)=50p+400[/tex]
Therefore, our required cost function would be [tex]C(p)=50p+400[/tex].
Answer:
Oranges
Step-by-step explanation:
Ryan is in the business of manufacturing phones. He must pay a daily fixed cost to rent the building and equipment, and also pays a cost per phone produced for materials and labor. The equation C=300+50pC=300+50p can be used to determine the total cost, in dollars, of producing pp phones in a given day. What is the yy-intercept of the equation and what is its interpretation in the context of the problem?