Respuesta :
The area of the triangle QRS which is made on a coordinate plane, and has points (negative 9, 5), (6, 10), and (2, negative 10) is 140 squared units.
How to find area of the triangle with coordinate points?
To find area of the triangle with coordinate points of vertex the following fomula is used.
[tex]A=|\dfrac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|[/tex]
Here, (x,y) are the coordinate points and subscript (1,2,3) are used for the three vertes of the triangle.
On a coordinate plane, triangle Q R S has points (-9, 5), (6, 10), and (2, -10). Thus the vertex points of triangle are,
[tex](x_1,x_2,x_3)=(-9,6,2)\\(y_1,y_2,y_3)=(5,10,-10)[/tex]
Put these values in the above formula,
[tex]A=|\dfrac{1}{2}[(-9)(10-(-10))+(6)(-10-5)+(2)(5-10)]|\\A=|\dfrac{1}{2}[-180-90-10]| \\A=140\rm\; units^2[/tex]
Thus, the area of the triangle QRS which is made on a coordinate plane, and has points (negative 9, 5), (6, 10), and (2, negative 10) is 140 squared units.
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