Answer:
x=2
Step-by-step explanation:
Based on your description I am assuming your equation is:
[tex] {9}^{ \frac{1}{2} } \times {9}^{ \frac{1}{2} } = \sqrt[x]{81} [/tex]
To find x in the above equation, we need to simplify the LHS
[tex] \sqrt{9} \times \sqrt{9} = \sqrt[x]{81} [/tex]
Combine the roots on the LHS
[tex]\sqrt{9 \times 9} = \sqrt[x]{81} [/tex]
We simplify further to get;
[tex] \sqrt{81} = \sqrt[x]{81} [/tex]
We can rewrite as
[tex] {81}^{ \frac{1}{2} } = {81}^{ \frac{1}{x} } [/tex]
By equating exponents we get:
[tex] \frac{1}{2} = \frac{1}{x} [/tex]
This implies that:
[tex]x = 2[/tex]
