Answer:
The answer to your question is 308.1 g of KmNO₄
Explanation:
Data
Volume = 6 L
Concentration = 0.325 M
Molar mass of Potassium permanganate = 39 + 55 + (16 x 4) = 158 g
Process
1.- Calculate the moles of KMnO₄
Formula
Molarity = moles/volume
moles = molarity x volume
moles = 0.325 x 6
moles = 1.95
2.- Calculate the grams of KMnO₄
158 g KMnO₄ ------------------ 1 mol
x ------------------ 1.95
x = (1.95 x 158)/1
x = 308.1 g
Answer:
We need 308.2 grams KMnO4
Explanation:
Step 1: Data given
Volume = 6.00L
Molarity of KMnO4 = 0.325 M
Molar mass KMnO4 = 158.034 g/mol
Step 2: Calculate moles KMnO4
Moles KMnO4 = volume * molarity
Moles KMnO4 = 6.00 L * 0.325 M
Moles KMnO4 = 1.95 moles
Step 3: Calculate mass KMnO4
Mass KMnO4 = moles KMnO4 * molar mass KMnO4
Mass KMnO4 = 1.95 moles * 158.034 g/mol
Mass KMnO4 = 308.2 grams
We need 308.2 grams KMnO4
