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Mary jogged from Point P to Point Q while Wyatt jogged from Point Q to Point P.
Point P and point Q are 7.5 kilometers apart.
Mary’s motion is represented by d = 8t and Wyatt’s motion is represented by 2d + 14t = 15, where t hours is the time and d kilometers is the distance from point P. Solve for linear equations. When did Mary and Wyatt meet? ____ minutes later
How far from point Q did they meet? ____km

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Answer:

When did Mary and Wyatt meet? 0.5 minutes later

How far from point Q did they meet? 3.5 km

Step-by-step explanation:

Mary’s motion is represented by d = 8t----(1)

Wyatt’s motion is represented by 2d + 14t = 15----(2)

We solve for d in equation (2) to get:d=7.5-7t----(3)

We equate equation (1) and (3) to get:

[tex]8t=7.5-7t[/tex]

We now solve for t to get:

[tex]8t+7t=7.5[/tex][tex]15t=7.5[/tex]

[tex]t=\frac{7.5}{15}=0.5[/tex]

Now put t=0.5 into equation (1) to get d=0.5*8=4

This means they met 4 km from point P.

Therefore they meet 7.5-4=3.5km from point Q

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