Answer:
Step-by-step explanation:
The given equation is
√b² + 3b - 2 = 4
The first step is to square the left hand side and the right hand side of the equation. It becomes
(√b² + 3b - 2)² = 4²
b² + 3b - 2 = 16
b² + 3b - 2 - 16 = 0
b² + 3b - 18 = 0
We would find two numbers such that their sum or difference is 3b and their product is -18b². The two numbers are 6b and - 3b. Therefore
b² + 6b - 3b - 18 = 0
b(b + 6) - 3(b + 6) = 0
b - 3 = 0 or b + 6 = 0
b = 3 or b = - 6
