Answer:
The expression is [tex]y=5,000(1.41)^5[/tex]
The number of transistors in a dense integrated circuit in 1979 is [tex]27,865\ transistors[/tex]
Step-by-step explanation:
we know that
The equation of a exponential growth function is equal to
[tex]y=a(1+r)^x[/tex]
where
y ----> is he number of transistors in a dense integrated circuit
x ----> is the number of years since year 1974
a ---> is the initial value or y-intercept
r ---> is the rate of change
In this problem we have
[tex]a=5,000\\r=41\%=41/100=0.41[/tex]
substitute
[tex]y=5,000(1+0.41)^x[/tex]
[tex]y=5,000(1.41)^x[/tex]
Find the number of transistors in a dense integrated circuit in 1979
we have that
x=1979-1974=5 years
substitute the value of x in the exponential equation
[tex]y=5,000(1.41)^5[/tex] -----> the expression
[tex]y=27,865\ transistors[/tex]
