if ac bisects bad and bcd prove bac=dac



ΔBAC ≅ ΔDAC by ASA congruency
Step-by-step explanation:
Congruency of any triangle can be proved by either of these four criteria. These include
SSS, SAS, ASA, AAS where S= sides and A= Angles
In the given figure ΔBAC & ΔDAC
Since the line, AC is a common angular bisector of ∠BAC and ∠DAC
∴ ∠BAC = ∠DAC ∵ AC is an angular bisector and bisects the ∠BAD into two halves
∠BCA=∠DCA ∵AC is an angular bisector and bisects the ∠DCB into two halves
AC=AC ∵Common side
∴ ΔBAC ≅ ΔDAC ⇒by Angle-Side-Angle (ASA) congruency criterion