Answer:
[tex]x=-5\\x=0\\x=3[/tex]
Step-by-step explanation:
I assume your equation to solve is
[tex](x+5)(x^2-3x)=0[/tex]
When we have a product of two factors equal to zero,
[tex]A\cdot B = 0[/tex]
The solution is either A = 0 or B = 0.
In this case, this means that we can break the equation into two equations:
[tex]x+5=0\\x^2-3x=0[/tex]
Solving the first one, we get:
[tex]x+5=0 \rightarrow x = -5[/tex]
For the second one, we rewrite it as:
[tex]x^2-3x=0\\x(x-3)=0[/tex]
And we see that this equation has two solutions:
[tex]x=0\\x=3[/tex]
Therefore, the three solutions are:
[tex]x=-5\\x=0\\x=3[/tex]
