The height will be 85.677 ft.
A particle is thrown into the air it traces the path of the parabola.
Given
initial velocity (u) = 41 ft/sec
Angle ([tex]\theta[/tex]) = 45
We know the equation of motion
[tex]v^{2} -u^{2} =2as[/tex]
In y direction
a = -9.81
v = 0
then
[tex]\begin{aligned} v^{2} -u^{2} &=2as\\0^{2} -41^{2} &=2(-9.81)h\\1681 &= 19.62h\\h &= 85.677\\\end{aligned}[/tex]
Thus, the height will be 85.677 ft.
More about the projectile link is given below.
https://brainly.com/question/2818076
