Answer:
[tex]6.1875\times 10^{-8}[/tex]
Explanation:
Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies [tex]I=\frac {k}{r^{2}}[/tex] where r is the distance
Since intensity is given then when at 3 m
[tex]1.1\times 10^{-7}= \frac {k}{3^{2}}[/tex]
[tex]k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}[/tex]
Since we have the constant then at 4m
Intensity, [tex]I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}[/tex]
