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A object with mass m=1.0kg is rotating around a axis,with a constant angular speed omega=6.28rad/s.The radius of the circular motion is 2.0m.What is the: (1) tangential speed;(2)centrapital force; and (3) period?

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muhammadjonedkhattak

Answer:

1) V =12.56 m/s, 2) F = 78.877 N, 3) T = 1 Sec

Explanation:

Given:

m=1 kg, ω=6.28 rad/s, r= 2.0m

1) Relation between linear and angular velocity is

V=rω = 2.0 m × 6.28 rad/s= 12.56 m/s

2) Centripetal force Fc=mv²/r

F= 1kg ( 12.56 m/s)²/2.0 m=78.877 N

3) Period of Revolution T= 2π/ω

T= 2π/6.28 rad/s = 1 sec

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