Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fractions. The number of tails in 4 tosses of a coin.

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Answer:

In simplified fraction, it is expressed as : 1/16, 1/4, 3/8, 1/4, 1/16.

Step-by-step explanation:

The discrete probability distribution for the random variable is as follows:

The number of tails possible in four tosses of a coin are 0,1,2,3,4

The total number of outcomes are  

The Probability distribution is

X 0 1 2 3 4

P(X)  1/16 4/16 6/16 4/16 1/16        

Therefore, In simplified fraction, it is expressed as : 1/16, 1/4, 3/8, 1/4, 1/16.

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The discrete probability distribution table for the outcome of tails obtainable from 4 coin tosses :

  • Number of tails __ 0 __1 __ 2 __ 3 __ 4
  • Probability ____ 1/16_1/4__3/8 _1/4 _1/16

Sample space for 4 coin tosess:

{HHHH, HHHT, HHHT, HHTT, HTHH, HTHT, HTHT, HTTT, THHH, THHT, THHT, THTT, TTHH, TTHT, TTHT, TTTT}

Recall :

[tex] probability = \frac{required \: outcome}{total \: possible \: outcomes} [/tex]

Possible Number of tails are 0, 1, 2, 3 and 4

For 0 tail :

P(0T) = [tex] \frac{1}{16} [/tex]

For 1 tail :

P(1T) = [tex] \frac{4}{16} = \frac{1}{4}[/tex]

For 2 tails :

P(2T) = [tex] \frac{6}{16} = \frac{3}{8}[/tex]

For 3 tails :

P(3T) = [tex] \frac{4}{16} = \frac{1}{4}[/tex]

For 4 tails :

P(4T) = [tex] \frac{1}{16}[/tex]

Therefore, the discrete probability distribution table is displayed thus :

  • Number of tails __ 0 __1 __ 2 __ 3 __ 4
  • Probability ____ 1/16 _1/4 _3/8 _1/4 _1/16

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