Answer:
[tex]\frac{2}{7}[/tex]
Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = [tex]\frac{1}{7}[/tex]
Remaining fuel after driving around the city = 1 - [tex]\frac{1}{7}[/tex]
= [tex]\frac{7 - 1}{7} = \frac{6}{7}[/tex]
According to question:
As from the rest of the gas in the car that is [tex]\frac{6}{7}[/tex], the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using = [tex]\frac{6}{7}[/tex] tank of gas.
The car can complete 1 trip by using = [tex]\frac{6}{7} \div 3[/tex]
=[tex]\frac{6}{7} \times\frac{1}{3}[/tex]
= [tex]\frac{6}{21}[/tex]
= [tex]\frac{2}{7}[/tex] tank of gas
Thus, [tex]\frac{2}{7}[/tex] tank of gas used for each complete trip to Ottawa.