A car starts with a dull tank of gas. After driving around 5he city, 1/7 of the gas has been used. With the rest of the gas in the car, the car can travel to and from Ottawa three times. What fractions of a tank of gas does each complete trip to Ottawa use?

Respuesta :

Answer:

[tex]\frac{2}{7}[/tex]

Step-by-step explanation:

Given:

A car starts with a dull tank of gas

1/7 of the gas has been used around the city.

With the rest of the gas in the car, the car can travel to and from Ottawa three times.

Question asked:

What fractions of a tank of gas does each complete trip to Ottawa use?

Solution:

Fuel used around the city = [tex]\frac{1}{7}[/tex]

Remaining fuel after driving around the city = 1 - [tex]\frac{1}{7}[/tex]

                                                                         =    [tex]\frac{7 - 1}{7} = \frac{6}{7}[/tex]

According to question:

As from the rest of the gas in the car that is [tex]\frac{6}{7}[/tex], the car can complete 3 trip to Ottawa  which means,

By unitary method:

The car can complete 3 trip by using = [tex]\frac{6}{7}[/tex] tank of gas.

The car can complete 1 trip by using =  [tex]\frac{6}{7} \div 3[/tex]

                                                             =[tex]\frac{6}{7} \times\frac{1}{3}[/tex]

                                                             =  [tex]\frac{6}{21}[/tex]

                                                             = [tex]\frac{2}{7}[/tex] tank of gas

Thus, [tex]\frac{2}{7}[/tex] tank of gas used for each complete trip to Ottawa.