A ball is thrown from a height of 164 feet with an initial downward velocity of 12 fts. The ball's height h (in feet) after seconds is given by the following.
h = 164 - 12t-16t^2?

Respuesta :

Answer:

≈ 2.85 or 3 seconds

Step-by-step explanation:

I understand the question is after how many seconds the ball hits the ground.

h= 0 is when ball hits the ground, then:

  • 164 - 12t - 16t² = 0
  • 4t² + 3t - 41= 0

Positive root of this quadratic equation is:

  • t = (-3 + √665)/8 ≈ 2.85 which is 3 seconds rounded to whole number