A mixture of 2.0 L of hydrogen and 2.0 L of oxygen at the same temperature and pressure react to form the theoretical yield of water vapor (at the same temperature and pressure). What is the expected final volume of the gas, in L?

The expected final volume of the gas if mixture of 2.0 L of hydrogen and 2.0 L of oxygen at the same temperature and pressure react to form the theoretical yield of water vapor, in L - 3L.

A mixture of 2 L of hydrogen and 2 L of oxygen gas at same temperature and pressure reacts to form theoretical yield of water vapor.

the reaction is represented by following equation:

2H₂ + O₂ → 2H₂O

according to the Avogadro's law equal volumes of gases contains equal number of moles at standard pressure and temperature.

from the equation,

2 moles of hydrogen gas reacts with one mole of oxygen gas to form 2 moles of water vapor

similarly, 2 L of hydrogen gas will react with 1 L of oxygen and form 2 L of water vapor, that left one L of oxygen gas.

Consumed:

2 L of hydrogen gas

1 L of oxygen gas

Remained:

1 L of oxygen

Released:

2 L of water vapor

total : remained + released

= 1 L + 2 L

= 3 L

Thus, the expected final volume of the gas if mixture of 2.0 L of hydrogen and 2.0 L of oxygen at the same temperature and pressure react to form the theoretical yield of water vapor, in L - 3L.

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