An 8.0-g bullet with a speed of 800 m/s is shot into a wooden block and penetrates 20 cm before stopping. What is the average force of the wood on the bullet? Assume the block does not move

Respuesta :

Answer:

The answer to your question is F = 16 N

Explanation:

Data

mass = 8 g

vo = 800 m/s

distance = 20 cm

force = ?

vf = 0 m/s

Process

1.- Calculate the acceleration of the bullet

Formula

  a = (vf² - vo²)/2d

Substitution

  a = (0 - 800)/2(0.2)

  a = -800/0.4

  a = 2000 m/s²

2.- Convert 8g to kg

           1000 g   --------------- 1 kg

                 8 g   -------------- x

             x = (8 x 1)/1000

             x = 0.008 kg

3.- Calculate the force

Formula

      F = ma

Substitution

      F = (0.008)(2000)

Simplification and result

      F = 16 N

The average force of the wood on the bullet is 16 N.

Calculation of the average force:

Since

mass = 8 g

vo = 800 m/s

distance = 20 cm

vf = 0 m/s

First we have to determine the acceleration by applying the following formula

a = (vf² - vo²)/2d

a = (0 - 800)/2(0.2)

a = -800/0.4

a = 2000 m/s²

Now  Convert 8g to kg

Since 1000 g   =  1 kg

So, 8 g should be 0.008 kg

Now the force is

F = ma

F = (0.008)(2000)

F = 16 N

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