Answer : The molarity of calcium ion on the original solution is, 0.131 M
Explanation :
The balanced chemical reaction is:
[tex]Ca(NO_3)_2+K_2CO_3\rightarrow CaCO_3+3KNO_3[/tex]
When calcium nitrate react with potassium carbonate to give calcium carbonate as a precipitate and potassium nitrate.
First we have to calculate the moles of [tex]CaCO_3[/tex]
[tex]\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}[/tex]
Given:
Mass of [tex]CaCO_3[/tex] = 0.524 g
Molar mass of [tex]CaCO_3[/tex] = 100 g/mol
[tex]\text{Moles of }CaCO_3=\frac{0.524}{100g/mol}=0.00524mol[/tex]
Now we have to calculate the concentration of [tex]CaCO_3[/tex]
[tex]\text{Concentration of }CaCO_3=\frac{\text{Moles of }CaCO_3}{\text{Volume of solution}}=\frac{0.00524mol}{0.040L}=0.131M[/tex]
Now we have to calculate the concentration of calcium ion.
As, calcium carbonate dissociate to give calcium ion and carbonate ion.
[tex]CaCO_3\rightarrow Ca^{2+}+CO_3^{2-}[/tex]
So,
Concentration of calcium ion = Concentration of [tex]CaCO_3[/tex] = 0.131 M
Thus, the concentration or molarity of calcium ion on the original solution is, 0.131 M
