Answer : The value of rate constant is, [tex]0.0327s^{-1}[/tex]
Explanation :
First we have to calculate the rate constant, we use the formula :
Expression for rate law for first order kinetics is given by:
[tex]k=\frac{2.303}{t}\log\frac{a}{a-x}[/tex]
where,
k = rate constant = ?
t = time passed by the sample = 4.84 s
a = initial concentration = 4.17 M
a - x = concentration after time 4.84 s = 3.56 M
Now put all the given values in above equation, we get
[tex]k=\frac{2.303}{4.84}\log\frac{4.17}{3.56}[/tex]
[tex]k=0.0327s^{-1}[/tex]
Therefore, the value of rate constant is, [tex]0.0327s^{-1}[/tex]
