Answer: The edge length of the unit cell is 0.461 nm
Explanation:
We are given:
Atomic radius of iridium = 0.163 nm
To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:
[tex]a=2\sqrt{2}R[/tex]
Putting values in above equation, we get:
[tex]a=2\sqrt{2}\times 0.163=0.461nm[/tex]
Hence, the edge length of the unit cell is 0.461 nm