Solution:
Given points are:
(6, -9) and (7, 1)
Let us find the slope of line
[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
From given,
[tex](x_1, y_1) = (6,-9)\\\\(x_2, y_2) = (7, 1)[/tex]
Therefore,
[tex]m = \frac{1+9}{7-6}\\\\m = \frac{10}{1}\\\\m = 10[/tex]
Thus slope of line is 10
The point slope form of line is given as:
[tex]y - y_1 = m(x-x_1)[/tex]
Substitute m = 10 and [tex](x_1, y_1)[/tex] = (6, -9) in above
[tex]y + 9 = 10(x - 6)[/tex]
Thus the equation of line in point slope form is found
