Answer:
95.0 nutritional calories
Explanation:
Given that:
One (1) nutritional Calorie = 1000 calories,
1 calorie = 4.184 J
Energy released when 1.0 g of a snack cake is combusted = Heat capacity(q) × temperature rise of the calorimeter ( ΔT)
= 10.0 kJ/°C × 1.42 °C
= 14.2 kJ
Energy released when 28 g snack cakes are used = 14.2 kJ × 28
= 397.6 kJ
In calories, the energy released = [tex]\frac{397.6*10^3J}{4.184J}[/tex] (since; 1 calorie = 4.184 J)
= 95028.68069
≅ 95.029 × 10³ calories
∴ the nutritional calories in one serving (28 g) of this snack cake can be calculated as:
= [tex]\frac{95.029*10^3calories}{1000 calories}[/tex]
= 95.029 nutritional calories
= 95.0 nutritional calories (to 3 significant figures)
∴ there are 95.0 nutritional calories in one serving (28 g) of this snack cake.
