Step-by-step explanation:
To verify, the identity [tex]\sin x \times \sec x=\tan x[/tex].
L.H.S. [tex]=\sin x \times \sec x[/tex]
We know that,
[tex]\sec A\cos A=1[/tex]
⇒ [tex]\sec A=\dfrac{1}{\cos A}[/tex]
Now, L.H.S., becomes
[tex]=\sin x \times \dfrac{1}{\cos x}[/tex]
[tex]=\dfrac{\sin x}{\cos x}[/tex]
= [tex]\tan x[/tex]
= R.H.S., verify.
Thus, [tex]\sin x \times \sec x=\tan x,[/tex] proved.