The mass of sodium chloride, NaCl that will be produced from 18 g of Na and 23 g of Cl₂ is 18.95 g
2Na + Cl₂ —> 2NaCl
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of Cl₂ = 2 × 35.5 = 71 g/mol
Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced equation = 2 × 58.5 = 58.5 g
SUMMARY
From the balanced equation above,
46 g of Na reacted with 71 g of Cl₂ to produce 58.5 g of NaCl
From the balanced equation above,
46 g of Na reacted with 71 g of Cl₂
Therefore,
18 g of Na will react with = (18 × 71) / 46 = 27.78 g of Cl₂
From the calculation made above, we can see clearly that a higher mass of Cl₂ (i.e 27.78 g) than what was given (i.e 23 g) is needed to react completely with 18 g of Na.
Therefore, Cl₂ is the limiting reactant.
From the balanced equation above,
71 g of Cl₂ reacted to produce 58.5 g of NaCl
Therefore,
23 g of Cl₂ will react to produce = (23 × 58.5) / 71 = 18.95 g of NaCl
Thus 18.95 g of NaCl were obtained from the reaction.
Learn more about stoichiometry:
https://brainly.com/question/14735801
#SPJ2
