Respuesta :
Answer:
Explanation:
The same current flows through each part of a series circuit. The total resistance of a series circuit is equal to the sum of individual resistances. Voltage applied to a series circuit is equal to the sum of the individual voltage drops.
I = 0.33 A
= 330 mA
Capacity, P = I × t
= 2050/330
= 6.21 hours
Time, t = 6.21 hours.
Total run time of light is 6.21 hour.
Energy consumed:
Given;
Maximum capacity = 2050 mAh
Emf = 1.20 V
The 3.6 V bulb takes 0.33 A
Find:
Total run time of light
Computation:
Total energy = 2050 mAh
Total energy = 3[(2050)(10⁻³)(3600)(1.2)]
Total energy = 26,568 J
Energy consumed per hour = VI
Energy consumed per hour = (3.6)(0.33)
Energy consumed per hour = 1.188 W
Total run time of light = E/t
Total run time of light = 26568 / 1.188
Total run time of light = 22,363.6 Second = 6.21 hour
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