Answer:
The specific rotation of the compound is +0.09°
Explanation:
Step 1: Data given
Mass of compound = 1.2 grams
Volume water = 10 mL
pathlength = 10 cm = 1 dm
Observed rotation of the compound = 0.75 °
Step 2: Calculate the specific rotation
[ α ] = α /(c*l)
⇒ with [ α ] = the specific rotation = TO BE DETERMINED
⇒ with α = the observed rotation = 0.75 °
⇒ with c = 1.2 grams of compound / 10 mL
⇒ with l = the pathlength = 10 cm = 1 dm
[ α ] = 0.75 ° / ((1.2grams /10mL)*1 dm)
[ α ] = +0.09°
The specific rotation of the compound is +0.09°
