Respuesta :
Answer : The
pH of a solution is, 8.56
Explanation : Given,
[tex]K_b=1.8\times 10^{-5}[/tex]
Concentration of ammonia (base) = 0.10 M
Concentration of ammonium nitrate (salt) = 0.55 M
First we have to calculate the value of [tex]pK_b[/tex].
The expression used for the calculation of [tex]pK_b[/tex] is,
[tex]pK_b=-\log (K_b)[/tex]
Now put the value of [tex]K_b[/tex] in this expression, we get:
[tex]pK_b=-\log (1.8\times 10^{-5})[/tex]
[tex]pK_b=5-\log (1.8)[/tex]
[tex]pK_b=4.7[/tex]
Now we have to calculate the pOH of buffer.
Using Henderson Hesselbach equation :
[tex]pOH=pK_b+\log \frac{[Salt]}{[Base]}[/tex]
Now put all the given values in this expression, we get:
[tex]pOH=4.7+\log (\frac{0.55}{0.10})[/tex]
[tex]pOH=5.44[/tex]
The pOH of buffer is 5.44
Now we have to calculate the pH of a solution.
[tex]pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56[/tex]
Thus, the pH of a solution is, 8.56
