Answer:
a) Poisson probability distribution model
b)
Mean=1.6.
Standard deviation=1.26.
c)
Mean=9.6.
Standard deviation=3.10.
Step-by-step explanation:
a)
The number of cases of salmonellosis has a rare frequency of occurring and also we can assume that trails are independent. So, the X the monthly count of salmonellosis cases in South Dakota is a Poisson random variable.
Thus, the appropriate probability distribution model for X is the Poisson probability distribution model.
b)
The mean and variance of the Poisson probability distribution model is μ the average number of salmonellosis cases per month in South Dakota.
Mean=E(x)=μ=1.6
Standard deviation=√V(x)=√μ=√1.6=1.26
c)
The average number of salmonellosis cases per month =1.6
The average number of salmonellosis cases over 6 months=6*1.6=9.6
The mean and variance of the Poisson probability distribution model is μ the average number of salmonellosis cases over 6 months in South Dakota.
Mean=E(x)=μ=9.6
Standard deviation=√V(x)=√μ=√9.6=3.10