The concentration of salt will be "39344 mg/L".
According to the question,
Storm sewer flow rate,
- [tex]Q_{se} = 2000 \ L/min[/tex]
Stream flow rate,
- [tex]Q_{st} = 2 \ m^3/s[/tex]
Sodium chloride,
- [tex]C_{se} = 1.2 \ g/L[/tex]
Sodium chloride concentration,
- [tex]C_{st} = 20 \ mg/L[/tex]
As we know,
→ [tex]Q = Q_{st} +Q_{se}[/tex]
→ [tex]Q_{st} = 2 \ m^3/s\times 1000 \ L/m^3\times 60 \ s/min[/tex]
→ [tex]Q = 120000+2000[/tex]
→ [tex]= 122000 \ L/min[/tex]
hence,
→ [tex]C_{min} = \frac{Q_{st}\times C_{st}+Q_{se} \ C_{se}}{Q}[/tex]
→ [tex]=\frac{120000\times 20+2000\times 1200}{122000}[/tex]
→ [tex]= 39344 \ mg/L[/tex]
Thus the above response is right.
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