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A current divider has an input current of 80 A, R1 with a value of 10 Ω, and R2 with a value of 14 Ω. What is the output current through R2? Assume units of A.

Respuesta :

Answer:

[tex]I_2=33.33\ A[/tex]

Explanation:

Given:

  • input current, [tex]i=80\ A[/tex]
  • first resistance in parallel,  [tex]R_1=10\ \Omega[/tex]
  • second resistance in parallel, [tex]R_2=14\ \Omega[/tex]

As we know that current is divided in the inverse ratio of the resistance in parallel by the nature current tries to flow through the path of minimum hindrance.

So, the current through the second resistor:

[tex]I_2=\frac{R_1}{R_1+R_2} \times i[/tex]

[tex]I_2=\frac{10}{10+14} \times 80[/tex]

[tex]I_2=33.33\ A[/tex]

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