The question is incomplete, here is the complete question:
A chemist adds 50.0 mL of a 0.277 M barium chloride solution to a flask. Calculate the mass in grams of barium chloride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.
Answer: The mass of barium chloride is 2.88 grams
Explanation:
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
Given mass of barium chloride = ? g
Molar mass of barium chloride = 208 g/mol
Molarity of solution = 0.277 M
Volume of solution = 50.0 mL
Putting values in above equation, we get:
[tex]0.277mol/L=\frac{\text{Mass of barium chloride}\times 1000}{208\times 50.0}\\\\\text{Mass of barium chloride}=\frac{0.277\times 208\times 50.0}{1000}=2.88g[/tex]
Hence, the mass of barium chloride is 2.88 grams