Respuesta :
Answer: The mole fraction of calcium chloride and water in the solution is 0.057 and 0.943 respectively
Explanation:
We are given:
Molality of calcium chloride = 3.35 m
This means that 3.35 moles of calcium chloride are present in 1 kg or 1000 g of water
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of water = 1000 g
Molar mass of water = 18.02 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of water}=\frac{1000g}{18.02g/mol}=55.49mol[/tex]
Total moles of solution = [3.35 + 55.49] = 58.84 moles
Mole fraction of a substance is given by:
[tex]\chi_A=\frac{n_A}{n_A+n_B}[/tex]
- For calcium chloride:
[tex]\chi_{CaCl_2}=\frac{n_{CaCl_2}}{n_{CaCl_2}+n_{H_2O}}\\\\\chi_{CaCl_2}=\frac{3.35}{58.84}=0.057[/tex]
- For water:
[tex]\chi_{H_2O}=\frac{n_{H_2O}}{n_{CaCl_2}+n_{H_2O}}\\\\\chi_{H_2O}=\frac{55.49}{58.84}=0.943[/tex]
Hence, the mole fraction of calcium chloride and water in the solution is 0.057 and 0.943 respectively
