A certain shop repairs both audio and video components. Let A denote the event that the next
component brought in for repair is an audio component, and let B be the event that the next component
is a compact disc player (so the event B is contained in A). Suppose that P(A)= 0.6 and P(B) =0.05.
What is P(B|A)?

Respuesta :

Answer:

0.12 is the required probability.

Step-by-step explanation:

We are given the following in the question:

A: next  component brought in for repair is an audio component

B: event that the next component  is a compact disc player

[tex]B \in A[/tex]

[tex]P(A)= 0.6\\P(B) =0.05[/tex]

We have to evaluate:

[tex]P(B|A) = \dfrac{P(B\cap A)}{P(A)}\\P(B|A) = \dfrac{P(B)}{P(A)}\\\\P(B|A) = \dfrac{0.05}{0.6} = 0.12[/tex]

0.12 is the required probability.