Answer:
Total distance, [tex]d=\dfrac{xyt}{(x+y)}[/tex]
Explanation:
It is given that,
Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.
We he moves from home to destination, time is equal to, [tex]\dfrac{d}{x}[/tex]
Similarly, when he move back to home, time taken is equal to [tex]\dfrac{d}{y}[/tex]
Total time taken is equal to :
[tex]\dfrac{d}{x}+\dfrac{d}{y}=t[/tex]
[tex]d(\dfrac{1}{x}+\dfrac{1}{y})=t[/tex]
[tex]d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}[/tex]
[tex]d=\dfrac{xyt}{(x+y)}[/tex]
So, the distance he speed in walking and jogging is [tex]\dfrac{xyt}{(x+y)}[/tex]. Hence, this is the required solution.
