Answer:
The answer to the question is
Only up to 1.45×10⁻³ grams of Ni(CO)₄ is allowable in the room
Explanation:
The allowable concentration of Ni(CO)₄ in a room is 1 ppb that is one part per billion, therefore
volume of gas in a room of 12 ft by 21 ft by 11 ft = 2772 ft³
From PV = nRT, n = (P×V)÷(R×T)
in SI units we have at 1 atm or 101325 Pa, V = 78.49 m³ R 3.142 J/mol·K
n = 101325×78.49/(3.142×298.15) = 8489.65 moles
The room can contain 8489.65 moles of Ni(CO)₄ However allowable concentration is 1 part per billion or
(8489.65/1000000000) moles = 8.49×10⁻⁶ moles
Molar mass of Ni(CO)₄ = 170.73 g/mol
Allowable mass of Ni(CO)₄ = Number of moles × molar mass
= 170.73 g/mol×8.49×10⁻⁶ moles = 1.45×10⁻³ grams
