A poll asked 1,060 adults if they would rate the quality of the environment in this country as "good." A total of 60% of the respondents replied "yes." What is the margin of error for a 94% confidence interval for the population proportion answering yes?

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Answer:

The answer to the question is

Margin of error = 2.83%

Step-by-step explanation:

The margin of error is the central range about the mean which provide a description of how accurate a given statistics sample information is in relation to the actual population. It is the radius of confidence of a statistic.

Margin of error for a proportion is given by

[tex]z*\sqrt{\frac{\rho(1-\rho)}{n} }[/tex]

Where

ρ = Sample proportion

n =  Sample size

z = z score, critical value at 94 % = 1.88

= 1.88*[tex]\sqrt{\frac{0.6*0.4}{1060} }[/tex] = +2.8×10⁻²

1.88×(0.6×0.4/1060)^0.5

= 0.0283

Converting to percentage gives 0.0283×100 = 2.83%

Margin of error = 2.83%