Answer:
Molar mass of KClO3 equals:
M(KCIO3) = M(K) + M(CI) + 3M(O) = 39.1 + 35.5 + 3×16.0 = 122.6 g
Mass of 2 moles of potassium chlorate equals:
2 × 122.6 = 245.2 g
Molar mass of O2 equals:
M(O2) = 2M(O) = 2 × 16.0 = 32.0 g
Mass of 3 moles of O2 equals:
3 ∙ 32.0 = 96 g
Therefore:
If 245.2 g of KClO3 produce 96.0 g of O2
34.4 g of KClO3 ‒ x g of O
Hence x =(34.4 × 96.0) ÷ 245.2
x = 13.47g
Answer:
Grams of oxygen produced = 13.47 grams
Explanation:
Firstly, let's balance the equation of the chemical reaction. Heating potassium trioxochlorate produces potassium chloride and oxygen molecules.
KClO 3 → KCl + O2
Balance the equation
2KClO3 → 2KCl + 3O2
From the chemical equation 2 moles of KClO3 decompose to produce 2 moles of KCl and 3 moles of Oxygen molecule.
atomic mass of K = 39.1g
atomic mass of Cl = 35.5g
atomic mass of O = 16g
The molecular mass of KClO3 = 39.1 + 35.5 + 16 × 3 = 122.6 g/mol
The mass of 2 moles of KClO3 = 2 × 122.6 = 245.2 g
molecular mass of O2 = 32 g
Mass of 3 moles of oxygen molecule = 3 × 32 = 96 grams
Using proportion
245.2g of KClO3 produces 96 g of oxygen
34.4 g will produce ? grams of Oxygen
Grams of oxygen produced = 34.4 × 96/245.2
Grams of oxygen produced = 3302.4 /245.2
Grams of oxygen produced = 13.4681892333
Grams of oxygen produced = 13.47 grams
