Answer:
Cost per day of operating lamp is $0.517.
Explanation:
Power consumed by the electric lamp is given by the relation:
P = I x V
Here I is current and V is the voltage of the lamp.
Substitute 1.45 A for I and 110 volts for V in the above equation.
P = 1.45 x 110 = 159.5 W
We know that 1 kW = 1000 W
So, we convert the power into kW;
P = [tex]\frac{159.5}{1000}[/tex] = 159.5 x 10⁻³ kW
Energy consumed by the electric lamp is given by the relation :
E = P x t
Here t is time.
Substitute 159.5 x 10⁻³ kW for P and 24 h for t in the above equation.
E = 159.5 x 10⁻³ x 24 = 3.828 kWh
Cost of energy from the electric company for 1 kWh = $0.135
Cost of energy operating a lamp per day = $ ( 0.135 x 3.828 )
= $ 0.517
Per day cost of operating lamp will be "$ 0.517".
According to the question,
Current, I = 1.45 A
Voltage, V = 110 V
Cost of energy = $0.135/kWh
We know the formula,
→ Power = Current × Voltage
or,
→ P = I × V
By substituting the values, we get
= [tex]1.45\times 110[/tex]
= [tex]159.5[/tex] W
By converting "W" into "kW", we get
= [tex]\frac{159.5}{1000}[/tex]
= [tex]159.5\times 10^{-3}[/tex] kW
Now,
The energy consumed be:
→ E = P × t
= [tex]159.5\times 10^{-3}\times 24[/tex]
= [tex]3.828[/tex] kWh
hence,
The per day cost of energy be:
= [tex](0.135\times 3.828)[/tex] $
= [tex]0.517[/tex] $
Thus the above answer is correct.
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