Respuesta :
Answer:
The wavelength of the 320 Hz sound waves in the column of air is 1070 mm.
Explanation:
To solve the question, we note that the tube acts as a pipe with one end closed and that a stationary wave is formed in the tube from the top, to the bottom of the tube and back.
The simplest and the first wave form in the tube has length L = Lambda/4
That is, a node at the closed end and an antinode at the open end
The second stationary wave is given by
l + 535 mm= 3/4×lambda
However v = f×lambda
f = v/lambda = v/(4l)
Therefore
Lambda/4 + 535 mm = 3/4lambda
Or 535 mm = 3/4lambda -Lambda/4 = lambda/2
Therefore, lambda = 2×535 mm = 1070 mm
The wavelength = 1070 mm
Answer:
Explanation:
Ln = 1/4 × (2n + 1)λ
where,
n = 0, 1, 2, 3, 4,...,
Ln = the length which is defined to be the distance measured from the open end of the tube to the water surface.
Ln = 1/4 × (2n + 1)λ
at n = 0,
L0 = 1/4 × λ
at n = 1,
L1 = 3/4 × λ
L1 - L0 = 1/2 × λ
535 × 2 = λ
λ = 1.07 m
