Given the following equation: 2 K + Cl2 ---> 2 KCl
How many moles of KCl are produced from 2.00 moles of K and excess Cl2?
A FULL STEP EXPLANATION WILL BE APPRECIATED

Respuesta :

Answer:

We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2

Explanation:

Step 1: Data given

Number of moles K = 2.00 moles

Cl2 is in excess, so K is the limiting reactant

Step 2: The balanced equation

2K + Cl2 → 2KCl

Step 3: Calculate moles KCl

For 2 moles K we need 1 mol Cl2 to produce 2 moles KCl

We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2

We produce 2.0 moles of KCl at the time when we have 2.00 moles K and and excess Cl2.

Calculation of the number of moles:

Since

Number of moles K = 2.00 moles

Cl2 is in excess, so K is the limiting reactant

Now The balanced equation is

2K + Cl2 → 2KCl

Now finally the moles of  KCl

For 2 moles K we need 1 mol Cl2 to produce 2 moles KCl

So, it required 2 moles.

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